c how many digits has a number
digits = (number == 0) ? 1 : (log10(number) + 1);
//or
while (number > 0)
{
number /= 10;
digits++;
}
//see: https://ideone.com/P1h8Nec how many digits has a number
digits = (number == 0) ? 1 : (log10(number) + 1);
//or
while (number > 0)
{
number /= 10;
digits++;
}
//see: https://ideone.com/P1h8Nec program to tell whether a number is an integer is even or odd
#include <stdio.h>
int main()
{
int Num;
printf("Test Data: ");
scanf("%d", &Num);
if(Num % 2 ==0)
{
printf("%d is an even integer", Num);
}
else
{
printf("%d is an odd integer", Num);
}
}Find Numbers with Even Number of Digits in c
/* Find Numbers with Even Number of Digits in c */
/**
* numDigit - gives the length of a given number
* @n: the number
*/
int numDigit(int n){
int d = 0;
while (n > 0 && n < 100000){
n = n/10;
d++;
}
return(d);
}
/**
* findNumbers - returns the number of numbers with even number of digits
* @*nums: a pointer to a num array
* @numSize: the size of the array
*/
int findNumbers(int* nums, int numsSize){
int c = 0;
for(int i = 0; i < numsSize; i++){
if(numDigit(nums[i]) % 2 == 0){
c++;
}
}
return(c);
}Copyright © 2021 Codeinu
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