Answers for "display image from file input"

7

input type="file" and display image

<p><input type="file"  accept="image/*" name="image" id="file"  onchange="loadFile(event)" style="display: none;"></p>
<p><label for="file" style="cursor: pointer;">Upload Image</label></p>
<p><img id="output" width="200" /></p>

<script>
var loadFile = function(event) {
	var image = document.getElementById('output');
	image.src = URL.createObjectURL(event.target.files[0]);
};
</script>
Posted by: Guest on June-08-2020
8

preview image file upload javascript

<input type="file" accept="image/*" onchange="loadFile(event)">
<img id="output"/>
<script>
  var loadFile = function(event) {
    var output = document.getElementById('output');
    output.src = URL.createObjectURL(event.target.files[0]);
    output.onload = function() {
      URL.revokeObjectURL(output.src) // free memory
    }
  };
</script>
Posted by: Guest on November-09-2020
0

preview image before upload

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form runat="server">
  <input type='file' id="imgInp" />
  <img id="blah" src="#" alt="your image" />
</form>

<script>
function readURL(input) {
  if (input.files && input.files[0]) {
    var reader = new FileReader();
    
    reader.onload = function(e) {
      $('#blah').attr('src', e.target.result);
    }
    
    reader.readAsDataURL(input.files[0]); // convert to base64 string
  }
}

$("#imgInp").change(function() {
  readURL(this);
});
</script>
Posted by: Guest on December-19-2020

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