Answers for "display image from input file"

7

input type="file" and display image

<p><input type="file"  accept="image/*" name="image" id="file"  onchange="loadFile(event)" style="display: none;"></p>
<p><label for="file" style="cursor: pointer;">Upload Image</label></p>
<p><img id="output" width="200" /></p>

<script>
var loadFile = function(event) {
	var image = document.getElementById('output');
	image.src = URL.createObjectURL(event.target.files[0]);
};
</script>
Posted by: Guest on June-08-2020
8

preview image file upload javascript

<input type="file" accept="image/*" onchange="loadFile(event)">
<img id="output"/>
<script>
  var loadFile = function(event) {
    var output = document.getElementById('output');
    output.src = URL.createObjectURL(event.target.files[0]);
    output.onload = function() {
      URL.revokeObjectURL(output.src) // free memory
    }
  };
</script>
Posted by: Guest on November-09-2020
0

using input file as html image source

$('document').ready(function () {
    $("#imgload").change(function () {
        if (this.files && this.files[0]) {
            var reader = new FileReader();
            reader.onload = function (e) {
                $('#imgshow').attr('src', e.target.result);
            }
            reader.readAsDataURL(this.files[0]);
        }
    });
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="file" id="imgload" >
<img src="#" id="imgshow" align="left">
Posted by: Guest on September-14-2020
1

how to display image before upload in jhtml

function display(input) {
   if (input.files && input.files[0]) {
      var reader = new FileReader();
      reader.onload = function(event) {
         $('#myid').attr('src', event.target.result);
      }
      reader.readAsDataURL(input.files[0]);
   }
}

$("#demo").change(function() {
   display(this);
});
Posted by: Guest on October-17-2020

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