Answers for "java Write a program to check Leap Year? Formula-A year is a leap, if it is divisible by 4 and 400. But, not by 100.(if-else statement)"

Leap year or not program in java using if-else

import java.util.Scanner;public class Main{public static void main(String[] args){int year;System.out.println("Enter the year");Scanner sc = new Scanner(System.in);year = sc.nextInt();if (((year % 4 == 0) && (year % 100!= 0)) || (year%400 == 0))System.out.println("it is a leap year");elseSystem.out.println("it is not a leap year");}}

Java program to find if given year is leap year

import java.util.Scanner;
public class LeapYearDemo
{
   public static void main(String[] args)
   {
      Scanner sc = new Scanner(System.in);
      System.out.println("Please enter any year: ");
      int year = sc.nextInt();
      boolean temp = false;
      if(year % 400 == 0)
      {
         temp = true;
      }
      else if(year % 100 == 0)
      {
         temp = false;
      }
      else if(year % 4 == 0)
      {
         temp = true;
      }
      else
      {
         temp = false;
      }
      if(temp)
      {
         System.out.println("Year " + year + " is a Leap Year");
      }
      else
      {
         System.out.println("Year " + year + " is not a Leap Year");
      }
      sc.close();
   }
}