XHR
var url = "https://example.com/";
var xhr = new XMLHttpRequest();
xhr.open("GET", url);
xhr.onreadystatechange = function () {
if (xhr.readyState === 4) {
console.log(xhr.status);
console.log(xhr.responseText);
}};
xhr.send();xhr
xhttp.open("POST", "demo_post2.asp", true);
xhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
xhttp.send("fname=Henry&lname=Ford");Copyright © 2021 Codeinu
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