sum all odd fibonacci numbers
function sumFibs(num) {
var prevNumber = 0;
var currNumber = 1;
var result = 0;
while (currNumber <= num) {
if (currNumber % 2 !== 0) {
result += currNumber;
}
currNumber += prevNumber;
prevNumber = currNumber - prevNumber;
}
return result;
}
// test here
sumFibs(4);sum all odd fibonacci numbers
const sumFibs = num => {
// Fibonacci always starts with a [1,1] so, we just initialize it
const fibNum = [1,1] // Get all the fibonacci numbers for that range
const fibOdd = [1,1] // Get all the odd fibonacci numbers for that range
// Loop for through for n times(num)
for(let i = 0; i < num; i++){
// Add the current index to the next index to get the later fib number
const fibAdd = fibNum[i] + fibNum[fibNum.length - 1]
if(fibAdd > num) break; // Stop pushing or looping if added indexes is more than number(num)
fibNum.push(fibAdd) // Push to all fibNum if added indexes is less than the number(num)
// Push odd fib numbers to fibOdd, so we can now uniquely add only odd numbers
if(fibAdd % 2 !== 0) fibOdd.push(fibAdd)
}
// Return reduced or added fibonacci odd numberss
return fibOdd.reduce((acc,cur) => acc + cur)
}
sumFibs(75024);
// With love @kouqharCopyright © 2021 Codeinu
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