convert js to python online
>>> import js2py
>>> f = js2py.eval_js('function f(x) {return x + x}')
>>> f(2)
4
>>> f()
nan
>>> f(f)
function f(x) { [python code] }function f(x) { [python code] }convert js to python online
>>> import js2py
>>> f = js2py.eval_js('function f(x) {return x + x}')
>>> f(2)
4
>>> f()
nan
>>> f(f)
function f(x) { [python code] }function f(x) { [python code] }convert from python to javascript online
l=int(input())
arr=list(map(int, input().split()))
arr=list(set(arr))
length_list=len(arr)
arr.sort()
#print("set = ",arr)
#print("length of set: ",length_list)
print(arr[length_list-2])convert from python to javascript online
def ArrayMatching(strArr):
x = [int(i) for i in strArr[0][1:-1].split(',')]
y = [int(i) for i in strArr[1][1:-1].split(',')]
sums = []
for i in range(max(len(x), len(y))):
total = 0
if i < len(x):
total += x[i]
if i < len(y):
total += y[i]
sums.append(str(total))
return '-'.join(sums)convert from python to javascript online
def choose_best_sum(t, k, ls):
most = 0
for i in range(len(ls)-1):
addN = 0
if i +k > len(ls) - 1:
break
for j in range(i,i+k-1):
addN += ls[j]
for p in range(i+k-1,len(ls)-1):
addN += ls[p]
if addN > most and addN <= t:
most = addN
addN -= ls[p]
else:
addN -= ls[p]
if most == 0:
return None
return mostpython convert to javascript online
def numberOfSubArray(arr):
data = {}
n = len(arr)
maxAmount = 1
for i in range(1, n + 1):
for j in range(i):
s = sum(arr[j:i])
if s not in data:
data[s] = [i - 1, 1]
elif data[s][0] < j:
data[s][1] += 1
if data[s][1] > maxAmount: maxAmount = data[s][1]
data[s][0] = i - 1
return maxAmountCopyright © 2021 Codeinu
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