Answers for "convert from python to javascript online"

convert js to python online

>>> import js2py
>>> f = js2py.eval_js('function f(x) {return x + x}')
>>> f(2)
4
>>> f()
nan
>>> f(f)
function f(x) { [python code] }function f(x) { [python code] }

convert from python to javascript online

l=int(input())
arr=list(map(int, input().split()))
arr=list(set(arr))
length_list=len(arr)

arr.sort()

#print("set = ",arr)
#print("length of set: ",length_list)

print(arr[length_list-2])

convert from python to javascript online

def ArrayMatching(strArr):
  x = [int(i) for i in strArr[0][1:-1].split(',')]
  y = [int(i) for i in strArr[1][1:-1].split(',')]
  sums = []

  for i in range(max(len(x), len(y))):
    total = 0
    if i < len(x):
      total += x[i]
    if i < len(y):
      total += y[i]
    sums.append(str(total))
  return '-'.join(sums)

convert from python to javascript online

def choose_best_sum(t, k, ls):
    most = 0

    for i in range(len(ls)-1):
        addN = 0
        if i +k > len(ls) - 1:
            break
        for j in range(i,i+k-1):
            addN += ls[j]
        for p in range(i+k-1,len(ls)-1):
            addN += ls[p]
            if addN > most and addN <= t:
                most = addN
                addN -= ls[p]
            else:
                addN -= ls[p]
    if most == 0:
        return None
    return most

python convert to javascript online

def numberOfSubArray(arr):
    data = {}
    n = len(arr)
    maxAmount = 1
    for i in range(1, n + 1):
        for j in range(i):
            s = sum(arr[j:i])
            if s not in data:
                data[s] = [i - 1, 1]
            elif data[s][0] < j:
                data[s][1] += 1
                if data[s][1] > maxAmount: maxAmount = data[s][1]
                data[s][0] = i - 1

    return maxAmount