how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))
how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))
error handling Pyhtin
# taking input from the user
try:
age = int(input("Please enter your age: "))
print(age)
except:
print("please enter a number instead! ")
print('bye')
# if you wanna ask their age until they enter the correct number use While Loop
while True:
try:
age = int(input("Please enter your age: "))
print(age)
except:
print("please enter a number instead! ")
else:
break
python except print error type
>>> try:
... raise Exception('spam', 'eggs')
... except Exception as inst:
... print(type(inst)) # the exception instance
... print(inst.args) # arguments stored in .args
... print(inst) # __str__ allows args to be printed directly,
... # but may be overridden in exception subclasses
... x, y = inst.args # unpack args
... print('x =', x)
... print('y =', y)
...
<class 'Exception'>
('spam', 'eggs')
('spam', 'eggs')
x = spam
y = eggs
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