how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))
how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))
python try except: print error
except Exception as e:
catch error data with except python
import sys
try:
S = 1/0 #Create Error
except: # catch *all* exceptions
e = sys.exc_info()
print(e) # (Exception Type, Exception Value, TraceBack)
############
# OR #
############
try:
S = 1/0
except ZeroDivisionError as e:
print(e) # ZeroDivisionError('division by zero')
python try except print error
1 (x,y) = (5,0)
2 try:
3 z = x/y
4 except ZeroDivisionError as e:
5 z = e # representation: "<exceptions.ZeroDivisionError instance at 0x817426c>"
6 print z # output: "integer division or modulo by zero"
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