Answers for "print the error in except python"

how to print error in try except python

try:
  # some code
except Exception as e:
	print("ERROR : "+str(e))

try except python

try:
  print("I will try to print this line of code")
except ERROR_NAME:
  print("I will print this line of code if error ERROR_NAME is encountered")

python except print error type

>>> try:
...     raise Exception('spam', 'eggs')
... except Exception as inst:
...     print(type(inst))    # the exception instance
...     print(inst.args)     # arguments stored in .args
...     print(inst)          # __str__ allows args to be printed directly,
...                          # but may be overridden in exception subclasses
...     x, y = inst.args     # unpack args
...     print('x =', x)
...     print('y =', y)
...
<class 'Exception'>
('spam', 'eggs')
('spam', 'eggs')
x = spam
y = eggs

python file open try except error

def FileCheck(fn):
    try:
      open(fn, "r")
      return 1
    except IOError:
      print "Error: File does not appear to exist."
      return 0

result = FileCheck("testfile")
print result

python check for exception

try: # put here the code that you expect to error 
  # code
except ValueError: # if you want to catch a ValueError
  # NOTE: you CANNOT catch a syntax error 
  # (UNLESS you are trying to execute code from a string with eval())
  
  # code if python caught the exception
except NameError: # you can catch multiple types of errors!
  # TIP: you can leave the error type blank to make python catch all types of errors!
  
  # code if another exception is caught (this is pretty much a modified if statement)
else: # if no error has been caught do the following:
  
  # code if no exception has been caught