how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))
how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))
try except python
try:
print("I will try to print this line of code")
except ERROR_NAME:
print("I will print this line of code if error ERROR_NAME is encountered")
python except print error type
>>> try:
... raise Exception('spam', 'eggs')
... except Exception as inst:
... print(type(inst)) # the exception instance
... print(inst.args) # arguments stored in .args
... print(inst) # __str__ allows args to be printed directly,
... # but may be overridden in exception subclasses
... x, y = inst.args # unpack args
... print('x =', x)
... print('y =', y)
...
<class 'Exception'>
('spam', 'eggs')
('spam', 'eggs')
x = spam
y = eggs
python file open try except error
def FileCheck(fn):
try:
open(fn, "r")
return 1
except IOError:
print "Error: File does not appear to exist."
return 0
result = FileCheck("testfile")
print result
python check for exception
try: # put here the code that you expect to error
# code
except ValueError: # if you want to catch a ValueError
# NOTE: you CANNOT catch a syntax error
# (UNLESS you are trying to execute code from a string with eval())
# code if python caught the exception
except NameError: # you can catch multiple types of errors!
# TIP: you can leave the error type blank to make python catch all types of errors!
# code if another exception is caught (this is pretty much a modified if statement)
else: # if no error has been caught do the following:
# code if no exception has been caught
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