Answers for "python except print error"

how to print error in try except python

try:
  # some code
except Exception as e:
	print("ERROR : "+str(e))

print type of exception python

try:
    someFunction()
except Exception as ex:
    template = "An exception of type {0} occurred. Arguments:\n{1!r}"
    message = template.format(type(ex).__name__, ex.args)
    print (message)

throwing an exception python

raise Exception("message")

catch error python

import traceback

dict = {'a':3,'b':5,'c':8}
try:
  print(dict[q])
 
except:
  traceback.print_exc()
  
# This will trace you back to the line where everything went wrong. 
# So in this case you will get back line 5

try except python

try:
  print("I will try to print this line of code")
except ERROR_NAME:
  print("I will print this line of code if error ERROR_NAME is encountered")

python except print error type

>>> try:
...     raise Exception('spam', 'eggs')
... except Exception as inst:
...     print(type(inst))    # the exception instance
...     print(inst.args)     # arguments stored in .args
...     print(inst)          # __str__ allows args to be printed directly,
...                          # but may be overridden in exception subclasses
...     x, y = inst.args     # unpack args
...     print('x =', x)
...     print('y =', y)
...
<class 'Exception'>
('spam', 'eggs')
('spam', 'eggs')
x = spam
y = eggs