how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))print type of exception python
try:
someFunction()
except Exception as ex:
template = "An exception of type {0} occurred. Arguments:\n{1!r}"
message = template.format(type(ex).__name__, ex.args)
print (message)catch error python
import traceback
dict = {'a':3,'b':5,'c':8}
try:
print(dict[q])
except:
traceback.print_exc()
# This will trace you back to the line where everything went wrong.
# So in this case you will get back line 5try except python
try:
print("I will try to print this line of code")
except ERROR_NAME:
print("I will print this line of code if error ERROR_NAME is encountered")python except print error type
>>> try:
... raise Exception('spam', 'eggs')
... except Exception as inst:
... print(type(inst)) # the exception instance
... print(inst.args) # arguments stored in .args
... print(inst) # __str__ allows args to be printed directly,
... # but may be overridden in exception subclasses
... x, y = inst.args # unpack args
... print('x =', x)
... print('y =', y)
...
<class 'Exception'>
('spam', 'eggs')
('spam', 'eggs')
x = spam
y = eggsCopyright © 2021 Codeinu
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