Answers for "python cattch exception and print"

2

catch error python

import traceback

dict = {'a':3,'b':5,'c':8}
try:
  print(dict[q])
 
except:
  traceback.print_exc()
  
# This will trace you back to the line where everything went wrong. 
# So in this case you will get back line 5
Posted by: Guest on October-25-2020
25

try except python

try:
  print("I will try to print this line of code")
except ERROR_NAME:
  print("I will print this line of code if error ERROR_NAME is encountered")
Posted by: Guest on February-01-2020

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