how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))
how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))
python try catch
try:
# Dangerous stuff
except ValueError:
# If you use try, at least 1 except block is mandatory!
# Handle it somehow / ignore
except (BadThingError, HorrbileThingError) as e:
# Hande it differently
except:
# This will catch every exception.
else:
# Else block is not mandatory.
# Dangerous stuff ended with no exception
finally:
# Finally block is not mandatory.
# This will ALWAYS happen after the above blocks.
try except python
try:
print("I will try to print this line of code")
except ERROR_NAME:
print("I will print this line of code if error ERROR_NAME is encountered")
python try except
try:
val = 1/0
except Exception as e:
raise Exception('ZeroDivisionError')
python file open try except error
def FileCheck(fn):
try:
open(fn, "r")
return 1
except IOError:
print "Error: File does not appear to exist."
return 0
result = FileCheck("testfile")
print result
try except python
age = input('age:')
try:
new_age = int(age)
except ValueError: # if age is not convertable to int
print('please enter a number...')
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