print type of exception python
try:
someFunction()
except Exception as ex:
template = "An exception of type {0} occurred. Arguments:n{1!r}"
message = template.format(type(ex).__name__, ex.args)
print (message)print type of exception python
try:
someFunction()
except Exception as ex:
template = "An exception of type {0} occurred. Arguments:n{1!r}"
message = template.format(type(ex).__name__, ex.args)
print (message)except as Exception:
>>> def catch():
... try:
... asd()
... except Exception as e:
... print e.message, e.args
...
>>> catch()
global name 'asd' is not defined ("global name 'asd' is not defined",)python exception
try:
# code block
except ValueError as ve:
print(ve)python try except
try:
print("I will try to print this line of code")
except Exception as e:
print(f"Error message: {}")try except python
def sum_of(x, y):
try:
print(x + y)
except TypeError:
print("Invalid argument specified.")try except example python
num1 , num2 = input("Give me two numbers: ").split(',')
try:
num1 = int(num1)
num2 = int(num2)
print(num1/num2)
except ZeroDivisionError:
print("your number2 is 0!")
except ValueError:
print("Please enter number")
except:
print("error")
#except TypeError:
#print("Cant sum int with str!")
#finally:
#print("end code")
finally:
print("error code finally")
print("end code")
#code by fawlidCopyright © 2021 Codeinu
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