map function using lambda in python
# Map function
nums1 = [2,3,5,6,76,4,3,2]
sq = list(map(lambda a : a*a, nums1))
print(sq)map function using lambda in python
# Map function
nums1 = [2,3,5,6,76,4,3,2]
sq = list(map(lambda a : a*a, nums1))
print(sq)find elements array lamda python
result = [filter(lambda x: (x % 2 == 0), [1, 2, 3])]Copyright © 2021 Codeinu
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