Answers for "df['recurr'] = df.apply(lambda x: True if len(df[(df.month == x.month + 1) & (df.name == x.name)])>"

use apply with lambda pandas

df.apply(lambda x: func(x['col1'],x['col2']),axis=1)

Posted by: Guest on November-14-2020

Code answers related to "df['recurr'] = df.apply(lambda x: True if len(df[(df.month == x.month + 1) & (df.name == x.name)])>"