python get args
import sys
print(sys.argv)python get args
import sys
print(sys.argv)variable number of arguments to python class
def multiply(*args):
z = 1
for num in args:
z *= num
print(z)
multiply(4, 5)
multiply(10, 9)
multiply(2, 3, 4)
multiply(3, 5, 10, 6)python *args
# concatenate_keys.py
def concatenate(**kwargs):
result = ""
# Iterating over the keys of the Python kwargs dictionary
for arg in kwargs:
result += arg
return result
print(concatenate(a="Real", b="Python", c="Is", d="Great", e="!"))args in python
# if args is not passed it return message
# "Hey you didn't pass the arguements"
def ech(num,*args):
if args:
a = []
for i in args:
a.append(i**num)
return a # return should be outside loop
else:
return "Hey you didn't pass the arguements" # return should be outside loop
print(ech(3))args in python
# normal parameters with *args
def mul(a,b,*args): # a,b are normal paremeters
multiply = 1
for i in args:
multiply *= i
return multiply
print(mul(3,5,6,7,8)) # 3 and 5 are being passed as a argument but 6,7,8 are argsargs in python
# if option is not passed it still returns 20
# if option = True or option = 1 is passed it returns 20 which is sum of numbers
# if option = False or option = 0 is passed it returns 0
def addition(a, b, *args, option=True):
result = 0
if option:
for i in args:
result += i
return a + b + result
else:
return resultCopyright © 2021 Codeinu
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