Answers for "pattern python rege"

pattern in python

rows = 6                        #Pattern(1,121,12321,1234321,123454321)
for i in range(1, rows + 1):
    for j in range(1, i - 1):
        print(j, end=" ")
    for j in range(i - 1, 0, -1):
        print(j, end=" ")
    print()

python regular expression

import re

# The string you want to find a pattern within
test_string = 'Hello greppers!'

# Creating a regular expression pattern
# This is a simple one which finds "Hello"
pattern = re.compile(r'Hello')

# This locates and returns all the occurences of the pattern
# within the test_string
match = pattern.finditer(test_string)

# Outputs all the ocurrences which were returned as 
# as match objects
for match in matches:
  print(match)