n highest salary in sql
SELECT TOP 1 salary
FROM (
SELECT DISTINCT TOP N salary
FROM #Employee
ORDER BY salary DESC
) AS temp
ORDER BY salary
n highest salary in sql
SELECT TOP 1 salary
FROM (
SELECT DISTINCT TOP N salary
FROM #Employee
ORDER BY salary DESC
) AS temp
ORDER BY salary
lowest salary in sql
SELECT first_name, last_name, salary, job_id
FROM employees
WHERE salary = (SELECT MIN(salary) FROM employees);
second highest salary in sql
SELECT MAX(SALARY) 'SECOND_MAX' FROM EMPLOYEES
WHERE SALARY <> (SELECT MAX(SALARY) FROM EMPLOYEES);
OR
Here is the solution for nth highest
salary from employees table
SELECT FIRST_NAME , SALARY FROM
(SELECT FIRST_NAME, SALARY, DENSE_RANK() OVER
(ORDER BY SALARY DESC) AS SALARY_RANK
FROM EMPLOYEES)
WHERE SALARY_RANK = n;
FIND LOWEST SALARY EARNER IN SQL
SELECT FIRST_NAME FROM EMPLOYEES
WHERE SALARY = (SELECT MIN(SALARY) FROM EMPLOYEES);
n highest salary in sql
SELECT salary FROM Employee ORDER BY salary DESC LIMIT N-1, 1
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