sql select second max
Both options you find max as a subset and then exclude from main select
sql> SELECT MAX( col ) FROM table
WHERE col < ( SELECT MAX( col ) FROM table);
sql> SELECT MAX(col) FROM table
WHERE col NOT IN (SELECT MAX(col) FROM table);second highest salary in sql
SELECT MAX(SALARY) 'SECOND_MAX' FROM EMPLOYEES
WHERE SALARY <> (SELECT MAX(SALARY) FROM EMPLOYEES);
OR
Here is the solution for nth highest
salary from employees table
SELECT FIRST_NAME , SALARY FROM
(SELECT FIRST_NAME, SALARY, DENSE_RANK() OVER
(ORDER BY SALARY DESC) AS SALARY_RANK
FROM EMPLOYEES)
WHERE SALARY_RANK = n;second max salary in sql
SELECT MAX(SALARY) 'SECOND_MAX' FROM EMPLOYEES
WHERE SALARY <> (SELECT MAX(SALARY) FROM EMPLOYEES);sql find second highest salary employee
/* sql 2nd highest salary employee */
select sal, ename
from emp
where sal =
(
select max(sal) from emp where sal <
(select max(sal) from emp)
)
----------------------------------------------- option 2
select *
from
(
select ename, sal, dense_rank() over(order by sal desc) rank
from emp
)
where rank =2;3rd highest salary in sql
Here is the solution for 3rd highest
salary from employees table
SELECT FIRST_NAME , SALARY FROM
(SELECT FIRST_NAME, SALARY, DENSE_RANK() OVER
(ORDER BY SALARY DESC) AS SALARY_RANK
FROM EMPLOYEES)
WHERE SALARY_RANK = 3;third highest salary in sql
SELECT ename,sal from Employee e1 where
N-1 = (SELECT COUNT(DISTINCT sal)from Employee e2 where e2.sal > e1.sal)Copyright © 2021 Codeinu
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