how to get second highest salary in each department in sql
SELECT E.Employers_name, E.dep_number, E.salary
FROM Employers E
WHERE 1 = (SELECT COUNT(DISTINCT salary)
FROM Employers B
WHERE B.salary > E.salary AND E.dep_number = B.dep_number)
group by E.dep_numbersecond highest salary in sql
SELECT MAX(SALARY) 'SECOND_MAX' FROM EMPLOYEES
WHERE SALARY <> (SELECT MAX(SALARY) FROM EMPLOYEES);
OR
Here is the solution for nth highest
salary from employees table
SELECT FIRST_NAME , SALARY FROM
(SELECT FIRST_NAME, SALARY, DENSE_RANK() OVER
(ORDER BY SALARY DESC) AS SALARY_RANK
FROM EMPLOYEES)
WHERE SALARY_RANK = n;sql find second highest salary employee
/* sql 2nd highest salary employee */
select sal, ename
from emp
where sal =
(
select max(sal) from emp where sal <
(select max(sal) from emp)
)
----------------------------------------------- option 2
select *
from
(
select ename, sal, dense_rank() over(order by sal desc) rank
from emp
)
where rank =2;Copyright © 2021 Codeinu
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