binary exponentiation modulo m
long long binpow(long long a, long long b, long long m) {
a %= m;
long long res = 1;
while (b > 0) {
if (b & 1)
res = res * a % m;
a = a * a % m;
b >>= 1;
}
return res;
}modular exponentiation
long long int PowMod(long long int x,long long int n,long long int M)
{
if(n<=1)
return x%M;
long long int res;
res=PowMod(x,n/2,M)%M;
res=(res*res)%M;
if(n%2==1)
res=((res%M)*(x%M))%M;
return res%M;
}Copyright © 2021 Codeinu
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