filter using two array of objects
const arr1 = [{id:'1',name:'A'},{id:'2',name:'B'},{id:'3',name:'C'},{id:'4',name:'D'}];
const arr2 = [{id:'1',name:'A',state:'healthy'},{id:'3',name:'C',state:'healthy'}];
const filterByReference = (arr1, arr2) => {
let res = [];
res = arr1.filter(el => {
return !arr2.find(element => {
return element.id === el.id;
});
});
return res;
}
console.log(filterByReference(arr1, arr2));filter out object in array using two arguments
var arr= [{id: "123", name: "Faa"},
{id: "123", name: "Bar"},
{id: "345", name: "Foo"},
{id: "678", name: "FaaBar"}
];
var name = 'FaaBar';
var id = '678';
arr = arr.filter(function(elem) {
//return false for the element that matches both the name and the id
return !(elem.id == id && elem.name == name)
});Copyright © 2021 Codeinu
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