find maximum number in array
#include <stdio.h>
int main() {
int i, n;
float arr[100];
printf("Enter the number of elements (1 to 100): ");
scanf("%d", &n);
for (i = 0; i < n; ++i) {
printf("Enter number%d: ", i + 1);
scanf("%f", &arr[i]);
}
// storing the largest number to arr[0]
for (i = 1; i < n; ++i) {
if (arr[0] < arr[i])
arr[0] = arr[i];
}
printf("Largest element = %.2f", arr[0]);
return 0;
}javascript get minimum value in array
// Getting min value
var arr = [5,1,9,5,7];
var min = Math.min(...arr);
console.log(min); // 1
// Getting max value
var arr = [5,1,9,5,7];
var min = Math.max(...arr);
console.log(min); // 9Minimum and maximum element in an Array
def divideAndConquer_Max(arr, ind, len):
maximum = -1;
if (ind >= len - 2):
if (arr[ind] > arr[ind + 1]):
return arr[ind];
else:
return arr[ind + 1];
maximum = divideAndConquer_Max(arr, ind + 1, len);
if (arr[ind] > maximum):
return arr[ind];
else:
return maximum;
def divideAndConquer_Min(arr, ind, len):
minimum = 0;
if (ind >= len - 2):
if (arr[ind] < arr[ind + 1]):
return arr[ind];
else:
return arr[ind + 1];
minimum = divideAndConquer_Min(arr, ind + 1, len);
if (arr[ind] < minimum):
return arr[ind];
else:
return minimum;
if __name__ == '__main__':
minimum, maximum = 0, -1;
# array initialization
arr = [6, 4, 8, 90, 12, 56, 7, 1, 63];
maximum = divideAndConquer_Max(arr, 0, 9);
minimum = divideAndConquer_Min(arr, 0, 9);
print("The minimum number in the array is: ", minimum);
print("The maximum number in the array is: ", maximum);Find Minimum array
Array -- Find Minimum
Write a method that can find the maximum number from an int Array
Solution 1:
public static void main(String[] args) {
int[] arr = new int[]{2,4,6,8,20};
System.out.println(maxValue(arr));
public static int maxValue( int[] n ) {
int min = Integer.MAX_VALUE;
for(int each: n)
if(each < min)
min = each;
return min;
}
Solution 2:
public static int maxValue( int[] n ) {
Arrays.sort( n );
return n [ 0 ];
}Copyright © 2021 Codeinu
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