Find the maximum number of an array js
var arr = [1, 2, 3];
var max = arr.reduce(function(a, b) {
return Math.max(a, b);
});Find the maximum number of an array js
var arr = [1, 2, 3];
var max = arr.reduce(function(a, b) {
return Math.max(a, b);
});find maximum number in array
#include <stdio.h>
int main() {
int i, n;
float arr[100];
printf("Enter the number of elements (1 to 100): ");
scanf("%d", &n);
for (i = 0; i < n; ++i) {
printf("Enter number%d: ", i + 1);
scanf("%f", &arr[i]);
}
// storing the largest number to arr[0]
for (i = 1; i < n; ++i) {
if (arr[0] < arr[i])
arr[0] = arr[i];
}
printf("Largest element = %.2f", arr[0]);
return 0;
}Find Maximum array
Array -- Find Maximum
Write a method that can find the maximum number from an int Array
Solution 1:
public static void main(String[] args) {
int[] arr = new int[]{2,4,6,8,20};
System.out.println(maxValue(arr));
public static int maxValue( int[] n ) {
int max = Integer.MIN_VALUE;
for(int each: n)
if(each > max)
max = each;
return max;
}
Solution 2:
public static int maxValue( int[] n ) {
Arrays.sort( n );
return n [ n.lenth-1 ];
}Find the maximum number of an array js
function getMaxOfArray(numArray) {
return Math.max.apply(null, numArray);
}how to find max in array
int[] a = new int[] { 20, 30, 50, 4, 71, 100};
int max = a[0];
for(int i = 1; i < a.length;i++)
{
if(a[i] > max)
{
max = a[i];
}
}
System.out.println("The Given Array Element is:");
for(int i = 0; i < a.length;i++)
{
System.out.println(a[i]);
}
System.out.println("From The Array Element Largest Number is:" + max);max element in array
int max;
max=INT_MIN;
for(int i=0;i<ar.length();i++){
if(ar[i]>max){
max=ar[i];
}Copyright © 2021 Codeinu
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