Answers for "haskell guards with where"

Haskell guards inside guards

f x | predicate1 =
         case () of                                -- () can only evaluate to ()
           () | predicate2 -> a
              | otherwise  -> b
    | otherwise  = c

haskell guards

f x | predicate1 = expression1 | predicate2 = expression2 | predicate3 = expression3