JS array sort
numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sortJS array sort
numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sortsort js
numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sortjavascript sort
var names = ["Peter", "Emma", "Jack", "Mia", "Eric"];
names.sort(); // ["Emma", "Eric", "Jack", "Mia", "Peter"]
var objs = [
{name: "Peter", age: 35},
{name: "Emma", age: 21},
{name: "Jack", age: 53}
];
objs.sort(function(a, b) {
return a.age - b.age;
}); // Sort by age (lowest first)js sort
let numbers = [4, 10, 5, 1, 3];
numbers.sort((a, b) => a - b);
console.log(numbers);
// [1, 2, 3, 4, 5]array sort js
arr = ['width', 'score', done', 'neither' ]
arr.sort() // results to ["done", "neither", "score", "width"]
arr.sort((a,b) => a.localeCompare(b))
// if a-b (based on their unicode values) produces a negative value,
// a comes before b, the reverse if positive, and as is if zero
//When you sort an array with .sort(), it assumes that you are sorting strings
//. When sorting numbers, the default behavior will not sort them properly.
arr = [21, 7, 5.6, 102, 79]
arr.sort((a, b) => a - b) // results to [5.6, 7, 21, 79, 102]
// b - a will give you the reverse order of the sorted items
//this explnation in not minejavascript sort
homes.sort(function(a, b) {
return parseFloat(a.price) - parseFloat(b.price);
});Copyright © 2021 Codeinu
Forgot your account's password or having trouble logging into your Account? Don't worry, we'll help you to get back your account. Enter your email address and we'll send you a recovery link to reset your password. If you are experiencing problems resetting your password contact us
