Answers for "array sort in js"

JS array sort

numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sort

javascript orderby

var items = [
  { name: 'Edward', value: 21 },
  { name: 'Sharpe', value: 37 },
  { name: 'And', value: 45 },
  { name: 'The', value: -12 },
  { name: 'Magnetic', value: 13 },
  { name: 'Zeros', value: 37 }
];

// sort by value
items.sort(function (a, b) {
  return a.value - b.value;
});

// sort by name
items.sort(function(a, b) {
  var nameA = a.name.toUpperCase(); // ignore upper and lowercase
  var nameB = b.name.toUpperCase(); // ignore upper and lowercase
  if (nameA < nameB) {
    return -1;
  }
  if (nameA > nameB) {
    return 1;
  }

  // names must be equal
  return 0;
});

js sort

strData = ["banana", "apple", "zebra", "jos"];
  numData = [1, 3, 2, 5, 6];
  objData = [
    { name: 'Alex', age: 20 },
    { name: 'Karlsson', age: 19 },
    { name: 'Noah', age: 21 },
  ];


  // sort str alfabeticly (a-z)
  strData.sort((a,b) => {
    return a === b ? 0 : a < b ? -1 : 1
  });
  console.log(strData)


  // sort Objdata uppifrån å ner (ålder 19-21)
  objData.sort((a,b) => a.age - b.age)
  console.log(objData);


  // Small number to large number
  numData.sort()
  console.log(numData);
  // Large number to small number
  numData.sort((a,b) => b-a)
  console.log(numData);

sort js

numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sort

javascript sort

var names = ["Peter", "Emma", "Jack", "Mia", "Eric"];
names.sort(); // ["Emma", "Eric", "Jack", "Mia", "Peter"]

var objs = [
  {name: "Peter", age: 35},
  {name: "Emma", age: 21},
  {name: "Jack", age: 53}
];

objs.sort(function(a, b) {
  return a.age - b.age;
}); // Sort by age (lowest first)

js sort

let numbers = [4, 10, 5, 1, 3];
numbers.sort((a, b) => a - b);
console.log(numbers);

// [1, 2, 3, 4, 5]