JS array sort
numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sort
JS array sort
numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sort
sort array java
Here’s the java program to sort an array using Arrays.sort() method.
import java.util.Arrays;
public class JavaArraySortMethod
{
public static void main(String[] args)
{
String[] strGiven = {"Great Barrier Reef", "Paris", "borabora", "Florence","tokyo", "Cusco"};
Arrays.sort(strGiven);
System.out.println("Output(case sensitive) : " + Arrays.toString(strGiven));
}
}
javascript sort
var names = ["Peter", "Emma", "Jack", "Mia", "Eric"];
names.sort(); // ["Emma", "Eric", "Jack", "Mia", "Peter"]
var objs = [
{name: "Peter", age: 35},
{name: "Emma", age: 21},
{name: "Jack", age: 53}
];
objs.sort(function(a, b) {
return a.age - b.age;
}); // Sort by age (lowest first)
array sort js
arr = ['width', 'score', done', 'neither' ]
arr.sort() // results to ["done", "neither", "score", "width"]
arr.sort((a,b) => a.localeCompare(b))
// if a-b (based on their unicode values) produces a negative value,
// a comes before b, the reverse if positive, and as is if zero
//When you sort an array with .sort(), it assumes that you are sorting strings
//. When sorting numbers, the default behavior will not sort them properly.
arr = [21, 7, 5.6, 102, 79]
arr.sort((a, b) => a - b) // results to [5.6, 7, 21, 79, 102]
// b - a will give you the reverse order of the sorted items
//this explnation in not mine
how to sort an array in javascript
const points = [40, 100, 1, 5, 25, 10];
points.sort(function(a, b){return a - b}); // for ascending
//another way for ascending
points.sort((a,b)=>{
if(a>b){
return 1
}else if(a<b){
return -1
}else{
return 0
}
})
points.sort(function(a, b){return b - a}); // for descending
//another way for descending
points.sort((a,b)=>{
if(a>b){
return -1
}else if(a<b){
return 1
}else{
return 0
}
})
javascript sort function
var points = [40, 100, 1, 5, 25, 10];
points.sort((a,b) => a-b)
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