Answers for "how sort function works in javascript"

sorting of arraray's number element in javascript

let numbers = [0, 1, 2, 3, 10, 20, 30];
numbers.sort((a, b) => a - b);

console.log(numbers);

sort js

numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sort

array sort js

arr = ['width', 'score', done', 'neither' ]
arr.sort() // results to ["done", "neither", "score", "width"]

arr.sort((a,b) => a.localeCompare(b)) 
// if a-b (based on their unicode values) produces a negative value, 
// a comes before b, the reverse if positive, and as is if zero

//When you sort an array with .sort(), it assumes that you are sorting strings
//. When sorting numbers, the default behavior will not sort them properly.
arr = [21, 7, 5.6, 102, 79]
arr.sort((a, b) => a - b) // results to [5.6, 7, 21, 79, 102]
// b - a will give you the reverse order of the sorted items 

//this explnation in not mine

javascript sort function

var points = [40, 100, 1, 5, 25, 10];
points.sort((a,b) => a-b)

how the sort function works javascript

const unsorted = ['d', 'd', 'h', 'r', 'v', 'z', 'f', 'c', 'g'];
const sorted = unsorted.sort();

console.log(sorted);
//["c", "d", "d", "f", "g", "h", "r", "v", "z"]


const unsortedNums = [45, 56, 3, 3, 4, 6, 7, 45, 1];
const sortedNums = unsortedNums.sort((a, b) => {
	return a - b;
});

console.log(sortedNums);
//[1, 3, 3, 4, 6, 7, 45, 45, 56]

sort() function example JavaScript

function ascendingOrder(arr) {
  return arr.sort(function(a, b) {
    return a - b;
  });
}
ascendingOrder([1, 5, 2, 3, 4]);