sorting of arraray's number element in javascript
let numbers = [0, 1, 2, 3, 10, 20, 30];
numbers.sort((a, b) => a - b);
console.log(numbers);sorting of arraray's number element in javascript
let numbers = [0, 1, 2, 3, 10, 20, 30];
numbers.sort((a, b) => a - b);
console.log(numbers);how the sort function works javascript
const unsorted = ['d', 'd', 'h', 'r', 'v', 'z', 'f', 'c', 'g'];
const sorted = unsorted.sort();
console.log(sorted);
//["c", "d", "d", "f", "g", "h", "r", "v", "z"]
const unsortedNums = [45, 56, 3, 3, 4, 6, 7, 45, 1];
const sortedNums = unsortedNums.sort((a, b) => {
return a - b;
});
console.log(sortedNums);
//[1, 3, 3, 4, 6, 7, 45, 45, 56]sort by ascending javascript
const months = ['March', 'Jan', 'Feb', 'Dec'];
months.sort();
console.log(months);
// expected output: Array ["Dec", "Feb", "Jan", "March"]Copyright © 2021 Codeinu
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