Answers for "sort array in ascending order javascript"

14

sorting array from highest to lowest javascript

// Sort an array of numbers 
let numbers = [5, 13, 1, 44, 32, 15, 500]

// Lowest to highest
let lowestToHighest = numbers.sort((a, b) => a - b);
//Output: [1,5,13,15,32,44,500]

//Highest to lowest
let highestToLowest = numbers.sort((a, b) => b-a);
//Output: [500,44,32,15,13,5,1]
Posted by: Guest on March-25-2020
5

javascript sort array smallest to largest

var numArray = [140000, 104, 99];
numArray.sort(function(a, b) {
  return a - b;
});

console.log(numArray);
Posted by: Guest on July-07-2020
1

Sort Ascending array

Array -- Sort Ascending
Write a return method that can sort an int array in Ascending order without using the sort method of the Arrays class
Solution 1:
public static void main(String[] args) {
    ArrayList<Integer> arr = new ArrayList<Integer>(5);
    arr.add(12);arr.add(4);arr.add(6);arr.add(8);arr.add(20);
    System.out.println(findMin(arr));
public static int[] Sort(int[] a) {
ArrayList<Integer> list=new ArrayList<Integer>();
for(int each: a)
list.add(each);
 
for(int i=0; i < a.length; i++) {
a[i] = findMin(list);
list.remove(Integer.valueOf(a[i]));
}
return a;
}
public static int findMin(ArrayList<Integer> a) {
int min =Integer.MAX_VALUE;
for(int each: a)
min = Math.min(min, each);
return min;
}
Solution 2:
public static void SortingArrayAsc(int[] arr) {
ArrayList<Integer> list = new ArrayList();
for(int each: arr) {
list.add(each);
}
for (int i = 0; i < list.size(); i++) {
            for (int j = 0; j < list.size(); j++) {
            if (list.get(i) < list.get(j)) {
                    Integer temp = list.get(i);
                    list.set(i, list.get(j));
                    list.set(j, temp);
            }
              }
}
for(int i=0; i < list.size(); i++) {
arr[i] = list.get(i);
}
Posted by: Guest on September-29-2021
13

javascript sort

var names = ["Peter", "Emma", "Jack", "Mia", "Eric"];
names.sort(); // ["Emma", "Eric", "Jack", "Mia", "Peter"]

var objs = [
  {name: "Peter", age: 35},
  {name: "Emma", age: 21},
  {name: "Jack", age: 53}
];

objs.sort(function(a, b) {
  return a.age - b.age;
}); // Sort by age (lowest first)
Posted by: Guest on May-21-2020
4

javascript sort

homes.sort((a, b) => parseFloat(a.price) - parseFloat(b.price));
Posted by: Guest on March-17-2020
1

sort by ascending javascript

const months = ['March', 'Jan', 'Feb', 'Dec'];
months.sort();
console.log(months);
// expected output: Array ["Dec", "Feb", "Jan", "March"]
Posted by: Guest on October-28-2020

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