Answers for "sort numbers in ascending order javascript"

9

javascript sort by numerical value

// Sort an array of numbers based on numerical value.
let numbers = [23, 65, 88, 12, 45, 99, 2000]

let sortednumbers = numbers.sort((a, b) => a - b);
//=> [12, 23, 45, 65, 88, 99, 2000]
Posted by: Guest on February-28-2020
5

javascript sort array smallest to largest

var numArray = [140000, 104, 99];
numArray.sort(function(a, b) {
  return a - b;
});

console.log(numArray);
Posted by: Guest on July-07-2020
0

js sort numbers descending order

// Sort Numbers in Descending Order
function sortDescending(num) {
	return Number(num.toString().split('').sort((a, b) => b - a).join(''));
//or: return parseInt(num.toString().split('').sort().reverse().join(''));
}

console.log(sortDescending(123)); // 321
console.log(sortDescending(1254859723)); // 9875543221
Posted by: Guest on March-12-2021
3

javascript ascending and descending

// ascending and discending for number
const arr1 = [21, 2100, 2, 35000];
const arr2 = [21, 2100, 2, 35000];

let ascN = arr1.sort((f, s) => f - s);
let dscN = arr2.sort((f, s) => s - f);

// ascending and discending for string
const arr3 = ['21', '2100', '2', '35000'];
const arr4 = ['21', '2100', '2', '35000'];

let ascS = arr3.sort((f, s) => f.length - s.length);
let dscS = arr4.sort((f, s) => s.length - f.length);
Posted by: Guest on June-21-2020
1

sort numbers in array javascript

function sortNumber(a, b) {
  return a - b;
}
Arr.sort(sortNumber);
Posted by: Guest on March-01-2020
0

sort array of numbers

numArray = numArray.sort((a, b) => a - b);
Posted by: Guest on June-25-2021

Code answers related to "sort numbers in ascending order javascript"

Browse Popular Code Answers by Language