Answers for "lambda x:x[1]"

Whatever

1

lambda x:x[1]

student_tuples = [
    ('john', 'A', 15),
    ('jane', 'B', 12),
    ('dave', 'B', 10),]
sorted(student_tuples, key=lambda student: student[2])   # sort by age
>>>>[('dave', 'B', 10), ('jane', 'B', 12), ('john', 'A', 15)]

Posted by: Guest on July-25-2020

Source

Code answers related to "lambda x:x[1]"

Code answers related to "Whatever"

Browse Popular Code Answers by Language

Python

Javascript

Whatever

Shell/Bash

CSS

Html

PHP

SQL

Java

C#