armstrong numbers
int main(){
int a;
cin >> a;
int check = a;
int sum = 0;
while(a!=0){
int rem = a%10;
sum += pow(rem,3); //include cmath
a/=10;
}
if(sum==check){
cout << "armstrong";
} else {
cout << "not armstrong";
}
return 0;
}Armstrong numbers
Numbers -- Armstrong numbers
Write a method that can check if a number is Armstrong number
Solution:
public static boolean ArmStrongNumber (int num) {
int a = 0, b =0, c= num;
while(num>0){
a=num%10;
num/=10;
b=b+(a*a*a);
}
if(c==b) {
return true;
}
return false;
}Copyright © 2021 Codeinu
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