armstrong numbers
int main(){
int a;
cin >> a;
int check = a;
int sum = 0;
while(a!=0){
int rem = a%10;
sum += pow(rem,3); //include cmath
a/=10;
}
if(sum==check){
cout << "armstrong";
} else {
cout << "not armstrong";
}
return 0;
}armstrong number
temp=n;
while(n>0)
{
r=n%10;
sum=sum+(r*r*r);
n=n/10;
}
if(temp==sum)
printf("armstrong number ");
else
printf("not armstrong number");
return 0;armstrong number
#include<stdio.h>
int main()
{
int num ,n,n1,c=0,mul=1,sum=0,r,f,i;
printf("enter any num: \n");
scanf("%d",&num);
n=num;
n1=num;
while(n!=0)
{
r=n%10;
c++;
n=n/10;
}
while (num!=0)
{
f=num%10;
mul=1;
for(i=1;i<=c;i++)
{
mul=mul*f;
}
sum=sum+mul;
num=num/10;
}
if(n1==sum)
printf("Armstrong Number");
else
printf("Not an Armstrong Number");
return 0;
}armstrong number function
def is_armstrong_number(number: int)-> bool:
arm = str(number)
lenght = len(arm)
sum = 0
for digit in arm:
sum += int(digit)**lenght
return sum == numberHow do you calculate Armstrong number in maths?
import java.util.Scanner;
import java.lang.Math;
public class one //ArmstsrongNumberExample
{
//function to check if the number is Armstrong or not
static boolean isArmstrong(int n)
{
int temp, digits=0, last=0, sum=0;
//assigning n into a temp variable
temp=n;
//loop execute until the condition becomes false
while(temp>0)
{
temp = temp/10;
digits++;
}
temp = n;
while(temp>0)
{
//determines the last digit from the number
last = temp % 10;
//calculates the power of a number up to digit times and add the resultant to the sum variable
sum += (Math.pow(last, digits));
//removes the last digit
temp = temp/10;
}
//compares the sum with n
if(n==sum)
//returns if sum and n are equal
return true;
//returns false if sum and n are not equal
else return false;
}
//driver code
public static void main(String args[])
{
int num;
Scanner sc= new Scanner(System.in);
System.out.print("Enter the limit: ");
//reads the limit from the user
num=sc.nextInt();
System.out.println("Armstrong Number up to "+ num + " are: ");
for(int i=0; i<=num; i++)
//function calling
if(isArmstrong(i))
//prints the armstrong numbers
System.out.print(i+ ", ");
}
}armstrong numbers
// Armstrong Numbers
1, 2, 3, 4, 5, 6, 7, 8, 9, 153, 370, 371, 407, 1634, 8208, 9474, 54748...Copyright © 2021 Codeinu
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