Answers for "all armstrong numbers"

2

armstrong numbers

int main(){
    
    int a;
    cin >> a;
    int check = a;
    int sum = 0;
    while(a!=0){
        int rem = a%10;
        sum += pow(rem,3);  //include cmath
        a/=10;
    }

    if(sum==check){
        cout << "armstrong";
    } else {
        cout << "not armstrong";
    }
    return 0;
}
Posted by: Guest on August-19-2021
2

armstrong number

temp=n;    
while(n>0)    
{    
r=n%10;    
sum=sum+(r*r*r);    
n=n/10;    
}    
if(temp==sum)    
printf("armstrong  number ");    
else    
printf("not armstrong number");    
return 0;
Posted by: Guest on January-09-2021
0

armstrong number function

def is_armstrong_number(number: int)-> bool:
    arm = str(number)
    lenght = len(arm)
    sum = 0
    for digit in arm:
        sum += int(digit)**lenght
    return sum == number
Posted by: Guest on June-01-2021
1

armstrong numbers

// Armstrong Numbers
1, 2, 3, 4, 5, 6, 7, 8, 9, 153, 370, 371, 407, 1634, 8208, 9474, 54748...
Posted by: Guest on June-13-2021
-1

Armstrong number

<form method="post">
        Enter the Number:
        <input type="number" name="number">
        <input type="submit" value="Submit">
    </form>
    <?php
    if ($_POST) {
        //get the number entered  
        $number = $_POST['number'];
        //store entered number in a variable  
        $a = $number;
        $sum  = 0;
        //run loop till the quotient is 0  
        while ($a != 0) {
            $rem   = $a % 10; //find reminder  
            $sum   = $sum + ($rem * $rem * $rem) || $sum = $rem; //cube the reminder and add it to the sum variable till the loop ends  
            $a   = $a / 10; //find quotient. if 0 then loop again  
        }
        //if the entered number and $sum value matches then it is an armstrong number  
        if ($number == $sum) {
            echo "Yes $number an Armstrong Number";
        } else {
            echo "$number is not an Armstrong Number";
        }
    }
//here is another example using while loop

$num=300;  
$total=0;  
$x=$num;  
while($x!=0){  
$rem=$x%10;  
$total=$total+($rem*$rem*$rem);  
$x=$x/10;  
}  
if($num==$total){
  echo "Yes it is an Armstrong number";}
else  
{echo "No it is not an armstrong number";}
Posted by: Guest on August-05-2020

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