Answers for "10 armstrong numbers"

armstrong numbers

int main(){
    
    int a;
    cin >> a;
    int check = a;
    int sum = 0;
    while(a!=0){
        int rem = a%10;
        sum += pow(rem,3);  //include cmath
        a/=10;
    }

    if(sum==check){
        cout << "armstrong";
    } else {
        cout << "not armstrong";
    }
    return 0;
}

armstrong numbers

// Armstrong Numbers
1, 2, 3, 4, 5, 6, 7, 8, 9, 153, 370, 371, 407, 1634, 8208, 9474, 54748...