Answers for "inverse square root fast"

3

fast inverse square root

float Q_rsqrt( float number )
{
	long i;
	float x2, y;
	const float threehalfs = 1.5F;

	x2 = number * 0.5F;
	y = number;
	i = * ( long * ) &y; // evil floating point bit level hacking
	i = 0x5f3759df - ( i >> 1 ); // what the fuck?
	y = * ( float * ) &i;
	y = y * ( threehalfs - ( x2 * y * y ) ); // 1st iteration
//	y = y * ( threehalfs - ( x2 * y * y ) ); // 2nd iteration, this can be removed

	return y;
}
Posted by: Guest on June-22-2021
3

fast inverse square root explained

float InvSqrt(float x){
        float xhalf = 0.5f * x;
        int i = *(int*)&x;            // store floating-point bits in integer
        i = 0x5f3759df - (i >> 1);    // initial guess for Newton's method
        x = *(float*)&i;              // convert new bits into float
        x = x*(1.5f - xhalf*x*x);     // One round of Newton's method
        return x;
    }
Posted by: Guest on December-13-2020

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