how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))print type of exception python
try:
someFunction()
except Exception as ex:
template = "An exception of type {0} occurred. Arguments:\n{1!r}"
message = template.format(type(ex).__name__, ex.args)
print (message)try except python
try:
print("I will try to print this line of code")
except ERROR_NAME:
print("I will print this line of code if error ERROR_NAME is encountered")catch error data with except python
import sys
try:
S = 1/0 #Create Error
except: # catch *all* exceptions
e = sys.exc_info()
print(e) # (Exception Type, Exception Value, TraceBack)
############
# OR #
############
try:
S = 1/0
except ZeroDivisionError as e:
print(e) # ZeroDivisionError('division by zero')python exception
try:
# code block
except ValueError as ve:
print(ve)python try except print error
1 (x,y) = (5,0)
2 try:
3 z = x/y
4 except ZeroDivisionError as e:
5 z = e # representation: "<exceptions.ZeroDivisionError instance at 0x817426c>"
6 print z # output: "integer division or modulo by zero"Copyright © 2021 Codeinu
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