Answers for "print where error is in except python"

4

print type of exception python

try:
    someFunction()
except Exception as ex:
    template = "An exception of type {0} occurred. Arguments:n{1!r}"
    message = template.format(type(ex).__name__, ex.args)
    print (message)
Posted by: Guest on July-13-2020
0

python defualt error handler

import sys
def my_except_hook(exctype, value, traceback):
    if exctype == KeyboardInterrupt:
        print "Handler code goes here"
    else:
        sys.__excepthook__(exctype, value, traceback)
sys.excepthook = my_except_hook
Posted by: Guest on August-27-2020

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