Answers for "list comprehension python with dictionary"

1

python set and dictionary comprehensions

simple_dict = {
    'a': 1,
    'b': 2
}
my_dict = {key: value**2 for key,value in simple_dict.items()}
print(my_dict)
#result = {'a': 1, 'b': 4}
Posted by: Guest on September-24-2020
5

dictionary comprehension python

square_dict = {num: num*num for num in range(1, 11)}
Posted by: Guest on May-28-2020
2

python dictionary comprehension

dict1 = {'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5}
# Double each value in the dictionary
double_dict1 = {k:v*2 for (k,v) in dict1.items()}
# double_dict1 = {'e': 10, 'a': 2, 'c': 6, 'b': 4, 'd': 8} <-- new dict
Posted by: Guest on November-29-2020
1

dictionary comprehension in python

# dictionary comprehension
# these are a little bit tougher ones than list comprehension

sample_dict = {
    'a': 1,
    'b': 2,
    'c': 3,
    'd': 4,
    'e': 5
}

# making squares of the numbers using  dict comprehension
square_dict = {key:value**2 for key, value in sample_dict.items()}
print(square_dict)

square_dict_even = {key:value**2 for key, value in sample_dict.items() if value % 2 == 0}
print(square_dict_even)

# if you don't have a dictionary and you wanna create a dictionary of a number:number**2
square_without_dict = {num:num**2 for num in range(11)}
print(square_without_dict)
Posted by: Guest on December-31-2020

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