Answers for "list comprehension for dictionary"

dictionary comprehension python

square_dict = {num: num*num for num in range(1, 11)}

python dictionary comprehension

dict1 = {'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5}
# Double each value in the dictionary
double_dict1 = {k:v*2 for (k,v) in dict1.items()}
# double_dict1 = {'e': 10, 'a': 2, 'c': 6, 'b': 4, 'd': 8} <-- new dict

dictionary comprehension

li = ['The', 'quick', 'brown', 'fox', 'was', 'quick']d = {k:1 for k in li}d #=> {'The': 1, 'quick': 1, 'brown': 1, 'fox': 1, 'was': 1}