dictionary comprehension python
square_dict = {num: num*num for num in range(1, 11)}dictionary comprehension python
square_dict = {num: num*num for num in range(1, 11)}python dictionary comprehension
dict1 = {'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5}
# Double each value in the dictionary
double_dict1 = {k:v*2 for (k,v) in dict1.items()}
# double_dict1 = {'e': 10, 'a': 2, 'c': 6, 'b': 4, 'd': 8} <-- new dicttypes of dict comprehension
# Dictionary Comprehension Types
{j:j*2 for i in range(10)}
#using if
{j:j*2 for j in range(10) if j%2==0}
#using if and
{j:j*2 for j in range(10) if j%2==0 and j%3==0}
#using if else
{j:(j*2 if j%2==0 and j%3==0 else 'invalid' )for j in range(10) }dictionary comprehension in python
# dictionary comprehension
# these are a little bit tougher ones than list comprehension
sample_dict = {
'a': 1,
'b': 2,
'c': 3,
'd': 4,
'e': 5
}
# making squares of the numbers using dict comprehension
square_dict = {key:value**2 for key, value in sample_dict.items()}
print(square_dict)
square_dict_even = {key:value**2 for key, value in sample_dict.items() if value % 2 == 0}
print(square_dict_even)
# if you don't have a dictionary and you wanna create a dictionary of a number:number**2
square_without_dict = {num:num**2 for num in range(11)}
print(square_without_dict)dictionary comprehension python
print({i:j for i,j in zip(txt_list,num) if i!="All"})dictionary comprehension
li = ['The', 'quick', 'brown', 'fox', 'was', 'quick']d = {k:1 for k in li}d #=> {'The': 1, 'quick': 1, 'brown': 1, 'fox': 1, 'was': 1}Copyright © 2021 Codeinu
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