Answers for "list comprehension python for dictionary"

dictionary comprehension python

square_dict = {num: num*num for num in range(1, 11)}

dictionary comprehension in python

# dictionary comprehension
# these are a little bit tougher ones than list comprehension

sample_dict = {
    'a': 1,
    'b': 2,
    'c': 3,
    'd': 4,
    'e': 5
}

# making squares of the numbers using  dict comprehension
square_dict = {key:value**2 for key, value in sample_dict.items()}
print(square_dict)

square_dict_even = {key:value**2 for key, value in sample_dict.items() if value % 2 == 0}
print(square_dict_even)

# if you don't have a dictionary and you wanna create a dictionary of a number:number**2
square_without_dict = {num:num**2 for num in range(11)}
print(square_without_dict)

dictionary comprehension python

print({i:j for i,j in zip(txt_list,num) if i!="All"})