dictionary comprehension python
square_dict = {num: num*num for num in range(1, 11)}dictionary comprehension python
square_dict = {num: num*num for num in range(1, 11)}python dictionary comprehension
dict1 = {'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5}
# Double each value in the dictionary
double_dict1 = {k:v*2 for (k,v) in dict1.items()}
# double_dict1 = {'e': 10, 'a': 2, 'c': 6, 'b': 4, 'd': 8} <-- new dictdictionary comprehension in python
# dictionary comprehension
# these are a little bit tougher ones than list comprehension
sample_dict = {
'a': 1,
'b': 2,
'c': 3,
'd': 4,
'e': 5
}
# making squares of the numbers using dict comprehension
square_dict = {key:value**2 for key, value in sample_dict.items()}
print(square_dict)
square_dict_even = {key:value**2 for key, value in sample_dict.items() if value % 2 == 0}
print(square_dict_even)
# if you don't have a dictionary and you wanna create a dictionary of a number:number**2
square_without_dict = {num:num**2 for num in range(11)}
print(square_without_dict)dictionary comprehension python
print({i:j for i,j in zip(txt_list,num) if i!="All"})Copyright © 2021 Codeinu
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